1.Substitution Method
Replacing one variable with an equivalent expression from another equation.
If $$x=y+k$$ Then $$a(y+k)+by=c$$
Example
Solve the system using substitution:
$$y = 2x + 1$$
$$3x + 2y = 16$$
Show solution
- Step 1: Substitute $$y = 2x + 1$$ into the second equation: $$3x + 2(2x + 1) = 16$$.
- Step 2: Expand: $$3x + 4x + 2 = 16 \Rightarrow 7x + 2 = 16$$.
- Step 3: Solve for x: $$7x = 14 \Rightarrow x = 2$$.
- Step 4: Substitute $$x = 2$$ back into $$y = 2x + 1$$: $$y = 2(2) + 1 = 5$$.
=> Conclusion: Solution is (2, 5).
Practice problems
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Problem 1
Solve using substitution:
$$x = y + 3$$
$$2x + y = 12$$
Show solution
Answer: $$(5, 2)$$
- Step 1: Substitute $$x = y + 3$$ into $$2x + y = 12$$: $$2(y + 3) + y = 12$$.
- Step 2: Expand: $$2y + 6 + y = 12 \Rightarrow 3y + 6 = 12$$.
- Step 3: Solve for y: $$3y = 6 \Rightarrow y = 2$$.
- Step 4: Calculate $$x = 2 + 3 = 5$$.
=> Conclusion: $$(x, y) = (5, 2)$$.
=> Correct Option: A ((5, 2)).
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Problem 2
Solve using substitution:
$$y = 3x - 5$$
$$2x + 3y = 7$$
Show solution
Answer: $$(2, 1)$$
- Step 1: Substitute $$y = 3x - 5$$ into $$2x + 3y = 7$$: $$2x + 3(3x - 5) = 7$$.
- Step 2: Expand: $$2x + 9x - 15 = 7 \Rightarrow 11x - 15 = 7$$.
- Step 3: Solve for x: $$11x = 22 \Rightarrow x = 2$$.
- Step 4: Calculate $$y = 3(2) - 5 = 1$$.
=> Conclusion: $$(x, y) = (2, 1)$$.
=> Correct Option: A ((2, 1)).
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Problem 3
Solve using substitution:
$$x - 2y = 4$$
$$3x + 5y = 1$$
Show solution
Answer: $$(2, -1)$$
- Step 1: Isolate x in the 1st equation: $$x = 2y + 4$$.
- Step 2: Substitute into 2nd equation: $$3(2y + 4) + 5y = 1$$.
- Step 3: Expand: $$6y + 12 + 5y = 1 \Rightarrow 11y + 12 = 1$$.
- Step 4: Solve for y: $$11y = -11 \Rightarrow y = -1$$.
- Step 5: Calculate $$x = 2(-1) + 4 = 2$$.
=> Conclusion: $$(x, y) = (2, -1)$$.
=> Correct Option: A ($$(2, -1)$$)
Best used when a variable has a coefficient of 1 or -1. It 'plugs' one equation into the other to create a single-variable equation.